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## Combined 8 Bank MCQ Question Solve

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### Combined 8 bank Questions solution With FDF File

**Combined 8 Bank Exam Date: 10 May 2019**

Exam Time: 10:30 AM to 11:30 AM

Exam type: MCQ

Post: Senior Officer (General)

Vacancy Number: 272450

**Combined 8 Bank Officer Question Solution**

Exam Taker: Arts Faculty (DU)

The 8 Banks/Financial Institutes and Vacancy was:

**See Combined 8 Bank Senior Officer Question Solution in below:**

**বাংলাঃ**

২১. কোনটি অশুদ্ধ- উর্দ্ধ

২২. কোনটি শুদ্ধ- স্বায়ত্তশাসন

২৩. পারিভাষিক শব্দ – সচিব

২৪. থিসরাস – অশোক মুখোপাধ্যায়

২৫. গরল এর বিপরীত – অমৃত

২৬. তৎসম – ধর্ম

২৭. সন্দেশ – রূঢ়ি

২৮. নিত্যসমাস – গ্রামান্তর

২৯. কার্তুজ – ফরাসি

৩০. ধ্বনি বাচক দিরুক্ত – কড়কড়

৩১. ♪কাঁদ +অন – কৃৎপ্রত্যয়

৩২. শ্রবন – ♪শ্রু+অন

৩৩. নিষ্ঠা – নিঃ+ঠা

৩৪. ষড়ানন – ষট + অানন

৩৫. কুশীলব – দ্বন্দ্বসমাস

৩৬. যে ব্যক্তি এক ঘর থেকে অন্য ঘরে ভিক্ষা করে বেড়াই – মাধুকরী

৩৭. চর্যাপদ – মাত্রাবৃত্ত

৩৮. লিপিমালা – রামরাম বসু

৩৯. জন্ডিস ও বেলুন – নাটক

৪০. শাহানামা – পারস্য

### Math:

41. In a business A and C invested amounts in the ratio 2:1 whereas A and B invested amounts in the ratio 3:2. If their annual profit be Tk. 157300, then B’s share in the profit is:

—

A : B = 3 : 2

A : C = 2 : 1

A : B : C = 6 : 4 : 3

B’s share = 157300 × 4/(6+4+3) = 48400. Ans: D

42. The average age of a group of 15 employees is 24 years. If 5 more employees join the group, the average age increases by 2 years. Find the average age of the new employees.

—

Sum of the ages of (15+5) = 20 employees => 20×(24+2) = 520 years

Sum of the ages of 15 employees => 15×24 = 360

of the ages of new 5 employees = (520-360) = 160

Average = 160/5 = 32. Ans: D

43. A person travels a certain distance at 3 km/hr and reachers 15 min late. If he travels at 4 km/hr, he reaches 15 min earlier. The distance he has to travel is:

—

D/4 – D/3 = (15+15)/60

D/12 = 1/2

D = 6 km. Ans: B

### Combined 3 Bank MCQ Question Solve here

44. The difference between the radii of bigger circle and smaller circle is 14 cm and the difference between their areas is 1056 cm². Radius of the smaller circle is :

—

π(x+14)² – πx² = 1056

π(x²+28x+196-x²) = 1056

28x+196 = 1056/π = 1056×7/22 = 336

x = (336-196)28 = 5. Ans: B

45. A sum fetches a simple interest of Tk. 6000 at the rate of 5% p.a. in 6 years. What would be the compound interest earned at the same rate of interest and the same principal in 2 years?

—

The sum = Tk. (6000×100)/(5×6) = Tk. 20000

Compound Interest = (20000 × 105/100 × 105/100) – 20000 = Tk. 2050. Ans: A

46. Alam sold an item for Tk. 6384 and incurred a loss of 30%. At what price should he have sold the item to have gained a profit of 30%?

—

Required price = Tk. 6384 × (100+30)/(100-30) = Tk. 11856. Ans: B

47. Kiran purchased a scooter for Tk. 52000. He sold it at loss of 10%. With that money he purchased another scooter and sold it at profit of 20%. What is his overall loss/profit?

## 8 Bank MCQ Question Solution

Selling price of the first scooter = Tk. 52000 × (100-10)/100 = Tk. 46800.

Loss on the first scooter = Tk. 52000×10% = Tk. 5200.

Profit on the second scooter = Tk. 46800×20% = Tk. 9360.

Net profit = Tk. (9360-5200) = Tk. 4160. Ans: D

48. A square is inscribed in a circle of diameter 2a and another square is circumscribing circle. The difference between the areas of outer and inner squares is:

—

Length of a side of the outer square = 2a.

Area = (2a)² = 4a².

Length of the diagonal of the inner square = 2a.

Length of a side of the inner square = 2a/√2

Area = (2a/√2)² = 4a²/2 = 2a²

Difference = 4a²-2a² = 2a². Ans: B

49. The average of nine numbers is 50. The average of the first five numbers is 54 and thatof the last three numbers is 52. Then the 6th number is:

—

The 6th number is = (50×9) – (5×54 + 3×52) = 450 – 426 = 24. Ans: D

### 3 Bank MCQ Question Solve here

50. A batsman has a certain average of runs for 12 innings. In the 13th inning, he scores 96 runs threby increasing his average by 5 runs. What is his average after the 13 innings?

—

Average of 12 innings = x

According to the question:

(12x+96)/13 = x+5

x = 96-65 = 31.

Average in 13 innings = 31+5 = 36 Ans: A

51. A man takes 3 hours 45 minutes to row a boat 22.5 km downstream of a river and 2 hours 30 minutes to cover a distance of 10 km upstream. Find hte speed of the river current in km/hr.

—

Speed of the boat = x kmph, the river current = y kmph.

3H45M = (3+ 45/60) hr = 15/4 hr

2H30M = (2+ 30/60) hr = 5/2 hr.

According to the question:

x+y = 22.5/(15/4) = 6

x-y = 10/(5/2) = 4

2x = 2

x = 1. Ans: A

52. A man can row 6 km/hr in still water. If the speed of the current is 2 km/hr, it takes 3 hrs more in upstream than in the downstream for the same distance. The distance is:

—

D/(6-2) – D/(6+2) = 3

D = 24. Ans: B

53. A train 150 m long passes a pole in 15 seconds and crosses another train of the same length travelling in opposite direction in 8 seconds. The speed of the second train in (km/h) is:

—

Speed of the first train = 150/15 = 10 mps.

speed of the second train = x mps.

According to the question:

x+10 = (150+150)/8

x = 27.5 mps = 27.5 × 3600/1000 = 99 kmph. Ans: D

## Bank MCQ Question Solution 2019 here

## Bangladesh Bank MCQ Question Solve 2019

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